Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-19 17:20Z
E = mc²
1θ² + 9θ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
310K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
98K
2H₂ + O₂ → 2H₂O
∫₀^∞ e^(-θ²) dθ = √π / 2
310K
\lim_{t\to 0} \frac{\sin t}{t} = 1
det| 3 6 ; 0 4 | = 12
45K
det| 7 1 ; 7 8 | = 49
10r² + 4r + 5 = 0