Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-19 17:23Z
E = mc²
1θ² + 9θ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
98K
2H₂ + O₂ → 2H₂O
det| 12 1 ; 5 13 | = 151
310K
\lim_{t\to 0} \frac{\sin t}{t} = 1
∫₀^∞ e^(-x²) dx = √π / 2
45K
det| 7 1 ; 7 8 | = 49
CH₄ + 2O₂ → CO₂ + 2H₂O
207K