Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-18 02:03Z
8t² + 6t + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
278K
2H₂ + O₂ → 2H₂O
det| 7 7 ; 4 8 | = 28
122K
∫₀^∞ e^(-x²) dx = √π / 2
163K
det| 9 1 ; 6 10 | = 84
∑_{k=1}^{n} k = n(n+1)/2
250K
det| 7 4 ; 4 8 | = 40
261K
∑_{k=1}^{n} k = n(n+1)/2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
ω = 2πf
2H₂ + O₂ → 2H₂O