Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-19 17:34Z
E = mc²
∫₀^∞ e^(-t²) dt = √π / 2
43K
1θ² + 9θ + 5 = 0
2H₂ + O₂ → 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
456K
det| 2 3 ; 5 3 | = -9
310K
\lim_{t\to 0} \frac{\sin t}{t} = 1
det| 9 4 ; 1 10 | = 86
45K
det| 7 1 ; 7 8 | = 49