Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-17 20:22Z
E = mc²
7β² + 3β + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
60K
λ = h/p
e^{i\pi} + 1 = 0
det| 1 8 ; 6 2 | = -46
∑_{k=1}^{n} k = n(n+1)/2
329K
1n² + 2n + 7 = 0
8β² + 2β + 4 = 0
∂θ/∂r = 1θ
CaCO₃ → CaO + CO₂