Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-18 23:21Z
6n² + 4n + 1 = 0
ΔS ≥ 0
∫₀^∞ e^(-φ²) dφ = √π / 2
163K
\frac{8}{9} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
250K
det| 10 2 ; 3 11 | = 104
261K
d/dω [ω^10] = 10ω^9
det| 9 4 ; 1 10 | = 86
352K
∇²β = 0
d/dr [r^4] = 4r^3