Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-17 23:14Z
∑_{k=1}^{n} k = n(n+1)/2
AgNO₃ + NaCl → AgCl↓ + NaNO₃
465K
\frac{6}{7} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
11θ² + 3θ + 2 = 0
det| 7 7 ; 6 8 | = 14
\binom{n}{k} = \frac{n!}{k!(n-k)!}
7ψ² + 4ψ + 3 = 0
2x² + 9x + 3 = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃