Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-18 23:54Z
6n² + 4n + 1 = 0
ΔS ≥ 0
∑_{k=1}^{n} k = n(n+1)/2
122K
\frac{8}{9} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
250K
d/dω [ω^10] = 10ω^9
∇²β = 0
det| 9 4 ; 1 10 | = 86
99K
det| 6 6 ; 5 7 | = 12
194K
d/dr [r^4] = 4r^3
∑_{k=1}^{n} k = n(n+1)/2
320K
∇ × E = −∂B/∂t