Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-19 17:32Z
E = mc²
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
43K
1θ² + 9θ + 5 = 0
\frac{4}{6} \sum_{i=1}^{n} i^{2}
310K
2H₂ + O₂ → 2H₂O
\lim_{t\to 0} \frac{\sin t}{t} = 1
456K
∑_{k=1}^{n} k = n(n+1)/2
310K
\lim_{t\to 0} \frac{\sin t}{t} = 1
det| 9 6 ; 0 10 | = 90
74K
det| 7 1 ; 7 8 | = 49
det| 9 4 ; 1 10 | = 86
401K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
207K
∑_{k=1}^{n} k = n(n+1)/2
438K