Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-18 23:07Z
6n² + 4n + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
109K
ΔS ≥ 0
∫₀^∞ e^(-φ²) dφ = √π / 2
163K
\frac{8}{9} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
250K
d/dω [ω^10] = 10ω^9
∇²β = 0
d/dr [r^4] = 4r^3
det| 9 5 ; 1 10 | = 85
320K
∇ × E = −∂B/∂t