Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-19 17:14Z
E = mc²
det| 7 4 ; 4 8 | = 40
329K
1θ² + 9θ + 5 = 0
2H₂ + O₂ → 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
310K
\lim_{t\to 0} \frac{\sin t}{t} = 1
det| 7 1 ; 7 8 | = 49
∑_{k=1}^{n} k = n(n+1)/2
401K
det| 11 5 ; 0 12 | = 132
207K
11θ² + 3θ + 6 = 0