Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-18 12:29Z
∇²ψ = 0
∑_{k=1}^{n} k = n(n+1)/2
278K
∫₀^∞ e^(-t²) dt = √π / 2
109K
1y² + 9y + 1 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
122K
∇²φ = 0
∑_{k=1}^{n} k = n(n+1)/2
250K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
261K
e^{i\pi} + 1 = 0
det| 7 4 ; 4 8 | = 40
349K
det| 3 7 ; 5 4 | = -23
∑_{k=1}^{n} k = n(n+1)/2
194K