Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-19 17:16Z
E = mc²
∫₀^∞ e^(-z²) dz = √π / 2
43K
1θ² + 9θ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
98K
2H₂ + O₂ → 2H₂O
\lim_{t\to 0} \frac{\sin t}{t} = 1
det| 9 4 ; 1 10 | = 86
74K
det| 1 8 ; 4 2 | = -30
401K
∑_{k=1}^{n} k = n(n+1)/2
207K
∫₀^∞ e^(-φ²) dφ = √π / 2
1K