Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-19 17:23Z
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
329K
1θ² + 9θ + 5 = 0
det| 7 4 ; 4 8 | = 40
310K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
98K
2H₂ + O₂ → 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
45K
∑_{k=1}^{n} k = n(n+1)/2
74K
∫₀^∞ e^(-α²) dα = √π / 2
401K