Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-19 02:54Z
d/dt [t^1] = 1t^0
det| 4 1 ; 4 5 | = 16
∑_{k=1}^{n} k = n(n+1)/2
310K
det| 7 8 ; 4 8 | = 24
98K
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
456K
∫₀^∞ e^(-θ²) dθ = √π / 2
207K
det| 9 1 ; 7 10 | = 83
438K