Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-19 17:21Z
E = mc²
det| 4 7 ; 2 5 | = 6
329K
1θ² + 9θ + 5 = 0
det| 11 9 ; 0 12 | = 132
310K
det| 7 4 ; 4 8 | = 40
98K
2H₂ + O₂ → 2H₂O
\lim_{t\to 0} \frac{\sin t}{t} = 1
∫₀^∞ e^(-φ²) dφ = √π / 2
45K
det| 7 1 ; 7 8 | = 49