Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-19 17:35Z
E = mc²
det| 7 7 ; 4 8 | = 28
329K
1θ² + 9θ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
310K
2H₂ + O₂ → 2H₂O
∫₀^∞ e^(-x²) dx = √π / 2
456K
det| 9 4 ; 1 10 | = 86
310K
\lim_{t\to 0} \frac{\sin t}{t} = 1
det| 7 1 ; 7 8 | = 49