Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-19 17:26Z
E = mc²
∫₀^∞ e^(-θ²) dθ = √π / 2
329K
1θ² + 9θ + 5 = 0
2H₂ + O₂ → 2H₂O
\lim_{t\to 0} \frac{\sin t}{t} = 1
∑_{k=1}^{n} k = n(n+1)/2
45K
det| 7 1 ; 7 8 | = 49
∫₀^∞ e^(-ψ²) dψ = √π / 2
401K
∫₀^∞ e^(-ψ²) dψ = √π / 2
207K