Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-17 22:23Z
N₂ + 3H₂ ⇌ 2NH₃
5α² + 5α + 4 = 0
∫₀^∞ e^(-r²) dr = √π / 2
60K
ΔS ≥ 0
∫₀^∞ e^(-n²) dn = √π / 2
119K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
11α² + 3α + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
329K
det| 7 4 ; 4 8 | = 40
180K