Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-18 23:33Z
6n² + 4n + 1 = 0
\lim_{ω\to 0} \frac{\sin ω}{ω} = 1
109K
ΔS ≥ 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
163K
\frac{8}{9} \sum_{i=1}^{n} i^{2}
d/dω [ω^10] = 10ω^9
∇²β = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O