Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-19 02:43Z
d/dt [t^1] = 1t^0
det| 7 4 ; 4 8 | = 40
43K
det| 4 1 ; 4 5 | = 16
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
310K
e^{i\pi} + 1 = 0
7α² + 6α + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
401K
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
438K