Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-18 23:21Z
6n² + 4n + 1 = 0
ΔS ≥ 0
∫₀^∞ e^(-x²) dx = √π / 2
122K
∑_{k=1}^{n} k = n(n+1)/2
163K
\frac{8}{9} \sum_{i=1}^{n} i^{2}
d/dω [ω^10] = 10ω^9
det| 11 5 ; 0 12 | = 132
349K
∇²β = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O