Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-18 02:03Z
8t² + 6t + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
109K
2H₂ + O₂ → 2H₂O
det| 2 7 ; 7 3 | = -43
163K
det| 9 1 ; 6 10 | = 84
∑_{k=1}^{n} k = n(n+1)/2
250K
∫₀^∞ e^(-θ²) dθ = √π / 2
352K
∑_{k=1}^{n} k = n(n+1)/2
349K