Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-19 19:35Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-ψ²) dψ = √π / 2
329K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
43K
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
310K
det| 11 6 ; 5 12 | = 102
\frac{4}{9} \sum_{i=1}^{n} i^{2}
310K
F = ma
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
45K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
401K