Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-17 22:56Z
N₂ + 3H₂ ⇌ 2NH₃
5α² + 5α + 4 = 0
∫₀^∞ e^(-φ²) dφ = √π / 2
60K
ΔS ≥ 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
∫₀^∞ e^(-φ²) dφ = √π / 2
255K
11α² + 3α + 4 = 0
det| 1 6 ; 4 2 | = -22
det| 9 4 ; 1 10 | = 86
180K