Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-17 22:23Z
N₂ + 3H₂ ⇌ 2NH₃
\binom{n}{k} = \frac{n!}{k!(n-k)!}
465K
5α² + 5α + 4 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
60K
ΔS ≥ 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 7 4 ; 4 8 | = 40
255K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
173K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
329K