Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-19 17:06Z
E = mc²
1θ² + 9θ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
310K
2H₂ + O₂ → 2H₂O
det| 7 4 ; 4 8 | = 40
456K
det| 2 2 ; 4 3 | = -2
310K
\lim_{t\to 0} \frac{\sin t}{t} = 1
CH₄ + 2O₂ → CO₂ + 2H₂O
74K
CH₄ + 2O₂ → CO₂ + 2H₂O
207K