Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-19 17:02Z
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
329K
det| 7 4 ; 4 8 | = 40
43K
1θ² + 9θ + 5 = 0
2H₂ + O₂ → 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
310K
\lim_{t\to 0} \frac{\sin t}{t} = 1
det| 9 5 ; 1 10 | = 85
45K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
74K
∫₀^∞ e^(-φ²) dφ = √π / 2
207K