Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-17 23:57Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
465K
\frac{6}{7} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
60K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
230K
∑_{k=1}^{n} k = n(n+1)/2
11θ² + 3θ + 2 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
255K
det| 7 4 ; 4 8 | = 40
329K