Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-22 23:40Z
det| 3 1 ; 6 4 | = 6
det| 7 4 ; 4 8 | = 40
370K
∂t/∂y = 4t
∑_{k=1}^{n} k = n(n+1)/2
126K
det| 11 7 ; 0 12 | = 132
det| 2 2 ; 4 3 | = -2
51K
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
51K
∇²z = 0
2H₂ + O₂ → 2H₂O
ω = 2πf
N₂ + 3H₂ ⇌ 2NH₃