Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-18 17:35Z
\frac{5}{6} \sum_{i=1}^{n} i^{2}
∫₀^∞ e^(-z²) dz = √π / 2
109K
iħ ∂ψ/∂t = Ĥψ
det| 7 4 ; 4 8 | = 40
122K
det| 11 7 ; 6 12 | = 90
AgNO₃ + NaCl → AgCl↓ + NaNO₃
det| 6 6 ; 5 7 | = 12
320K
∑_{k=1}^{n} k = n(n+1)/2
341K