Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-18 23:38Z
6n² + 4n + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
278K
ΔS ≥ 0
\lim_{r\to 0} \frac{\sin r}{r} = 1
163K
\frac{8}{9} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
250K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
99K
\frac{1}{7} \sum_{i=1}^{n} i^{2}
194K