Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-19 02:09Z
d/dt [t^1] = 1t^0
det| 9 8 ; 3 10 | = 66
43K
det| 4 1 ; 4 5 | = 16
det| 7 4 ; 4 8 | = 40
310K
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
310K
det| 9 1 ; 7 10 | = 83
45K
det| 9 6 ; 0 10 | = 90
401K
∫₀^∞ e^(-t²) dt = √π / 2
207K