Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-19 17:33Z
E = mc²
1θ² + 9θ + 5 = 0
2H₂ + O₂ → 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
456K
\lim_{t\to 0} \frac{\sin t}{t} = 1
det| 7 1 ; 7 8 | = 49
11θ² + 3θ + 6 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
d/dr [r^5] = 5r^4