Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-19 17:36Z
E = mc²
\binom{n}{k} = \frac{n!}{k!(n-k)!}
329K
1θ² + 9θ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
310K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
98K
2H₂ + O₂ → 2H₂O
\lim_{t\to 0} \frac{\sin t}{t} = 1
det| 7 1 ; 7 8 | = 49
∑_{k=1}^{n} k = n(n+1)/2
401K
det| 12 1 ; 5 13 | = 151
207K
11θ² + 3θ + 6 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}