Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-18 23:27Z
6n² + 4n + 1 = 0
∫₀^∞ e^(-t²) dt = √π / 2
109K
ΔS ≥ 0
\frac{8}{9} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
250K
det| 2 8 ; 7 3 | = -50
261K
d/dω [ω^10] = 10ω^9
∇²β = 0
∑_{k=1}^{n} k = n(n+1)/2
320K