Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-18 02:03Z
8t² + 6t + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
278K
∫₀^∞ e^(-t²) dt = √π / 2
109K
2H₂ + O₂ → 2H₂O
det| 2 7 ; 7 3 | = -43
122K
det| 9 1 ; 6 10 | = 84
det| 9 6 ; 0 10 | = 90
261K
∑_{k=1}^{n} k = n(n+1)/2
det| 9 4 ; 1 10 | = 86
352K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 10 7 ; 3 11 | = 89
99K