Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-18 02:02Z
8t² + 6t + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
278K
2H₂ + O₂ → 2H₂O
det| 4 8 ; 3 5 | = -4
163K
det| 9 1 ; 6 10 | = 84
det| 9 8 ; 3 10 | = 66
261K
∑_{k=1}^{n} k = n(n+1)/2
det| 2 3 ; 5 3 | = -9
352K
det| 7 4 ; 4 8 | = 40
349K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
99K
2H₂ + O₂ → 2H₂O