Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-19 17:20Z
E = mc²
1θ² + 9θ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
310K
2H₂ + O₂ → 2H₂O
\lim_{t\to 0} \frac{\sin t}{t} = 1
det| 9 4 ; 1 10 | = 86
74K
det| 7 1 ; 7 8 | = 49
10r² + 4r + 5 = 0
11θ² + 3θ + 6 = 0