Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-17 23:29Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
465K
\frac{6}{7} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
CH₄ + 2O₂ → CO₂ + 2H₂O
119K
∫₀^∞ e^(-φ²) dφ = √π / 2
173K
∑_{k=1}^{n} k = n(n+1)/2
368K