Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-18 23:34Z
6n² + 4n + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
109K
ΔS ≥ 0
∑_{k=1}^{n} k = n(n+1)/2
163K
\frac{8}{9} \sum_{i=1}^{n} i^{2}
d/dω [ω^10] = 10ω^9
∑_{k=1}^{n} k = n(n+1)/2
99K
det| 9 1 ; 7 10 | = 83
194K
det| 7 4 ; 4 8 | = 40
320K