Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-19 02:11Z
d/dt [t^1] = 1t^0
∑_{k=1}^{n} k = n(n+1)/2
43K
det| 4 1 ; 4 5 | = 16
det| 7 8 ; 4 8 | = 24
310K
∫₀^∞ e^(-φ²) dφ = √π / 2
98K
N₂ + 3H₂ ⇌ 2NH₃
∫₀^∞ e^(-φ²) dφ = √π / 2
310K
e^{i\pi} + 1 = 0
7α² + 6α + 3 = 0