Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-17 23:56Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
465K
\frac{6}{7} \sum_{i=1}^{n} i^{2}
det| 2 2 ; 4 3 | = -2
60K
CH₄ + 2O₂ → CO₂ + 2H₂O
230K
∑_{k=1}^{n} k = n(n+1)/2
det| 7 4 ; 4 8 | = 40
119K
11θ² + 3θ + 2 = 0
det| 7 7 ; 6 8 | = 14
det| 1 8 ; 4 2 | = -30
329K
∑_{k=1}^{n} k = n(n+1)/2
368K
7ψ² + 4ψ + 3 = 0
2x² + 9x + 3 = 0