Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-17 23:56Z
∑_{k=1}^{n} k = n(n+1)/2
\frac{6}{7} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-φ²) dφ = √π / 2
119K
∫₀^∞ e^(-θ²) dθ = √π / 2
152K
11θ² + 3θ + 2 = 0
∫₀^∞ e^(-ψ²) dψ = √π / 2
368K