Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-19 17:02Z
E = mc²
1θ² + 9θ + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
310K
2H₂ + O₂ → 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
456K
det| 7 4 ; 4 8 | = 40
310K
\lim_{t\to 0} \frac{\sin t}{t} = 1
det| 7 1 ; 7 8 | = 49
∑_{k=1}^{n} k = n(n+1)/2
207K
11θ² + 3θ + 6 = 0
∫₀^∞ e^(-θ²) dθ = √π / 2
438K
\binom{n}{k} = \frac{n!}{k!(n-k)!}