Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-19 02:36Z
d/dt [t^1] = 1t^0
det| 4 1 ; 4 5 | = 16
∫₀^∞ e^(-n²) dn = √π / 2
310K
N₂ + 3H₂ ⇌ 2NH₃
e^{i\pi} + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
45K
7α² + 6α + 3 = 0
∫₀^∞ e^(-θ²) dθ = √π / 2
207K
det| 12 1 ; 5 13 | = 151
1K