Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-17 20:13Z
E = mc²
∑_{k=1}^{n} k = n(n+1)/2
465K
7β² + 3β + 4 = 0
λ = h/p
e^{i\pi} + 1 = 0
det| 9 4 ; 1 10 | = 86
255K
det| 1 8 ; 6 2 | = -46
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
329K
1n² + 2n + 7 = 0