Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-18 17:08Z
\frac{5}{6} \sum_{i=1}^{n} i^{2}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
278K
iħ ∂ψ/∂t = Ĥψ
det| 2 6 ; 0 3 | = 6
122K
det| 7 4 ; 4 8 | = 40
163K
det| 11 7 ; 6 12 | = 90
∑_{k=1}^{n} k = n(n+1)/2
250K
\frac{4}{9} \sum_{i=1}^{n} i^{2}
261K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
\binom{n}{k} = \frac{n!}{k!(n-k)!}
352K