Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-17 23:29Z
∑_{k=1}^{n} k = n(n+1)/2
\frac{6}{7} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
11θ² + 3θ + 2 = 0
det| 7 7 ; 6 8 | = 14
∑_{k=1}^{n} k = n(n+1)/2
329K
∫₀^∞ e^(-ψ²) dψ = √π / 2
368K