Reaction Log /sym/649cc0
id=1 · host=co.gridbatch.net · 2026-10-18 02:03Z
8t² + 6t + 4 = 0
\frac{7}{1} \sum_{i=1}^{n} i^{2}
278K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
109K
2H₂ + O₂ → 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
122K
\binom{n}{k} = \frac{n!}{k!(n-k)!}
163K
det| 9 1 ; 6 10 | = 84
∑_{k=1}^{n} k = n(n+1)/2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
349K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
2H₂ + O₂ → 2H₂O
3x² + 6x + 3 = 0